Electrons with de Broglie wavelength λ fall on the target in an X - ray tube. The cut-off…
Physics · NEET · NTA Exams — Dual Nature of Matter and Radiation
Electrons with de Broglie wavelength λ fall on the target in an X - ray tube. The cut-off wavelength of the emitted X - rays is
- \(\lambda_{g}=\frac{2 m c \lambda^{2}}{h}\)
- \(\lambda_{\mathrm{I}}=\frac{2 \mathrm{~h}}{\mathrm{mc}}\)
- \(\lambda_{g}=\frac{2 m^{2} c^{2} \lambda^{2}}{h^{2}}\)
- \(\lambda_{g}=\lambda\)
Answer
(B) _ I = 2 ~h mc
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