Two equal drops of water are falling through air with a steady velocity of 10 cm/s. If…

Physics · NEET · NTA Exams — Properties of Solids and Liquids

Two equal drops of water are falling through air with a steady velocity of 10 cm/s. If the drops recombine to form a single heavy drop, the terminal velocity of heavy drop is
  1. \(1 \times 2^{\frac{2}{3}} \mathrm{~cm} / \mathrm{s}\)
  2. \(10 \times 2^{\frac{2}{3}} \mathrm{~cm} / 5\)
  3. \(20 \times 2^{\frac{2}{3}} \mathrm{~cm} / \mathrm{s}\)
  4. \(10 \times 2^{3} \mathrm{~cm} / \mathrm{s}\)

Answer

(B) 10 2^ 2 3 ~cm / 5

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