In the given reaction scheme, P is a phenyl alkyl ether, Q is an aromatic compound; R and…
Chemistry · JEE Advanced · NTA Exams — Alcohols, Phenols and Ethers
In the given reaction scheme, P is a phenyl alkyl ether, Q is an aromatic compound; R and S are the major products.
\[\boldsymbol{P} \xrightarrow{\mathrm{HI}} Q \xrightarrow[\text { (iii) } \mathrm{H}_{3} \mathrm{O}^{+}]{\substack{\text { (i) } \mathrm{NaOH} \\ \text { (ii) } \mathrm{CO}_{2}}} R \xrightarrow[\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}]{\text {(i) }\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}} S\]
The correct statement about S is
\[\boldsymbol{P} \xrightarrow{\mathrm{HI}} Q \xrightarrow[\text { (iii) } \mathrm{H}_{3} \mathrm{O}^{+}]{\substack{\text { (i) } \mathrm{NaOH} \\ \text { (ii) } \mathrm{CO}_{2}}} R \xrightarrow[\text { (ii) } \mathrm{H}_{3} \mathrm{O}^{+}]{\text {(i) }\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}} S\]
The correct statement about S is
- it primarily inhibits noradrenaline degrading enzymes.
- it inhibits the synthesis of prostaglandin.
- it is a narcotic drug.
- it is ortho-acetylbenzoic acid.
Answer
(B) it inhibits the synthesis of prostaglandin.
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