1 mole of oxalic acid is treated with conc. H 2 SO 4 . The resultant gaseous mixture is…
Chemistry · JEE Advanced · NTA Exams — Some Basic Concepts in Chemistry
1 mole of oxalic acid is treated with conc. H2SO4. The resultant gaseous mixture is passed through a solution of KOH. The mass of KOH consumed will be (where KOH absorbs CO2.)
(COOH)2 \(\xrightarrow{\mathrm{H}_{2} \mathrm{SO}_{4}}\) CO + CO2 + H2O
2 KOH + CO2 \(\text { ⟶ }\)K2CO3 + H2O
(COOH)2 \(\xrightarrow{\mathrm{H}_{2} \mathrm{SO}_{4}}\) CO + CO2 + H2O
2 KOH + CO2 \(\text { ⟶ }\)K2CO3 + H2O
- 28 g
- 56 g
- 84 g
- 112 g
Answer
(D) 112 g
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