A particle is projected at an angle of 60o above the horizontal with a speed of 10 m/s…

Physics · JEE Advanced · NTA ExamsKinematics

A particle is projected at an angle of 60o above the horizontal with a speed of 10 m/s. After some time the direction of its velocity makes an angle of 30o above the horizontal. The speed of the particle at this instant is
  1. \(\frac{5}{\sqrt{3}} \mathrm{~m} / \mathrm{s}\)
  2. \(5 \sqrt{3} \mathrm{~m} / \mathrm{s}\)
  3. 5 m/s
  4. \(\frac{10}{\sqrt{3}} \mathrm{~m} / \mathrm{s}\)

Answer

(D) 10 3 ~m / s

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