A reactant (A) forms two products A k _ 1 B, Activation energy E_ a_ 1 A k _ 2 C, Activation energy E _ a _ 2 If E _ a _ 2 =2 E _ a _ 1 , then k 1 and k 2 are

A reactant (A) forms two products A k _ 1 B, Activation energy E_ a_ 1 A k _ 2 C…

Chemistry · JEE Main · NTA Exams — Chemical Kinetics

A reactant (A) forms two products
A \(\xrightarrow{\mathrm{k}_{1}}\) B, Activation energy \(E_{a_{1}}\)
A \(\xrightarrow{\mathrm{k}_{2}}\) C, Activation energy \(\mathrm{E}_{\mathrm{a}_{2}}\)
If \(\mathrm{E}_{\mathrm{a}_{2}}=2 \mathrm{E}_{\mathrm{a}_{1}},\) then k₁ and k₂ are

\(\mathrm{k}_{1}=2 \mathrm{k}_{2} \mathrm{e}^{\mathrm{E}_{\mathrm{a}_{2}} / \mathrm{RT}}\)
\(\mathrm{k}_{1}=\mathrm{k}_{2} \mathrm{e}^{\mathrm{E}_{\mathrm{a}_{1}} / \mathrm{RT}}\)
\(\mathrm{k}_{2}=\mathrm{k}_{1} \mathrm{e}^{\mathrm{E}_{\mathrm{a}_{2}} / \mathrm{RT}}\)
\(\mathrm{k}_{1}=\mathrm{Ak}_{2} \mathrm{e}^{\mathrm{E}_{\mathrm{a}_{1}} / \mathrm{RT}}\)

Answer

(B) k _ 1 = k _ 2 e ^ E _ a _ 1 / RT

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A reactant (A) forms two products A k _ 1 B, Activation energy E_ a_ 1 A k _ 2 C…

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