On the basis of kinetic theory of gases, the mean kinetic energy of 1 mole per degree of…
Physics · JEE Main · NTA Exams — Kinetic Theory of Gases
On the basis of kinetic theory of gases, the mean kinetic energy of 1 mole per degree of freedom is:
- \(\frac{1}{2} \mathrm{kT}\)
- \(\frac{1}{2} \mathrm{RT}\)
- \(\frac{3}{2} \mathrm{kT}\)
- \(\frac{3}{2} \mathrm{RT}\)
Answer
(A) 1 2 kT
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