Compound A, C _ 5 H _ 10 O _ 5 , given a tetraacetate with A c_ 2 O and oxidation of A…
Chemistry · JEE Main · NTA Exams — Biomolecules
Compound A, \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{5}\), given a tetraacetate with \(A c_{2} O\) and oxidation of A with \(\mathrm{Br}_{2}-\mathrm{H}_{2} \mathrm{O}\) gives an acid, \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}_{6}\). Reduction of A with HI gives isopentane. The possible structure of A is :
(Jee Main 2023)
(Jee Main 2023)
Answer
(A)
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements. One is labelled as Assertion and the other is labelled as Reason. Assertion…
- Glycosidic linkage between C 1 of a -glucose and C 2 of -fructose is found in (JEE Main 2022)
- The incorrect statement about Glucose is: (Jee Main 2024)
- Acid or enzymatic hydrolysis of sucrose to give an equimolar mixture of glucose and fructose is called
- Following tetrapeptide can be represented as (F, L, D, Y, I, Q, P are one letter codes for amino acids) (Jee…
- The number of tripeptides formed by three different amino acids are
- In polysaccharides, the linkage connecting monosaccharides is called
- D-Glucose [ ] HNO _ 3 (A), Product (A) is



