The correct expression for the rate constant for reactions of zero order is
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
The correct expression for the rate constant for reactions of zero order is
- k = [A0]/2t
- \(\mathrm{k}=\frac{1}{\mathrm{t}}\left\{\left[\mathrm{~A}_{0}\right]-[\mathrm{A}]\right\}\)
- \(\mathrm{k}=\frac{1}{\mathrm{t}}\left\{[\mathrm{~A}]-[\mathrm{A}]_{0}\right\}\)
- \(\mathrm{k}=\frac{2.303}{\mathrm{t}} \log \left\{\left[\mathrm{~A}_{0}\right]-[\mathrm{A}]\right\}\)
Answer
(B) k = 1 t [ ~A _ 0 ]-[ A ]
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