The function f: R- 0 R is given by f(x)= 1 x - 2 e^ 2 x -1 can be made continuous at x=0…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
The function \(f: R-\{0\} \rightarrow R\) is given by \(f(x)=\frac{1}{x}-\frac{2}{e^{2 x}-1}\) can be made continuous at \(x=0\) by defining \(f(0)\) as
- \(2\)
- \(\pi\)
- \(0\)
- \(1\)
Answer
(A) 2
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