The value of K c for the following equilibrium is CaCO 3( s ) CaO ( s ) + CO 2( g ) …
Chemistry · Class 11 · CBSE — Equilibrium
The value of Kc for the following equilibrium is
CaCO3(s)
CaO(s) + CO2(g). Given Kp = 167 bar at 1073 K.
CaCO3(s)
CaO(s) + CO2(g). Given Kp = 167 bar at 1073 K.- 1.896 mol L–1
- 4.38 × 10–4 mol L–1
- 6.3 × 104 mol L–1
- 6.626 mol L–1
Answer
(B) 4.38 × 10 –4 mol L –1
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