KOH (V 1 mL , xN) is mixed with NaOH (V 2 mL , yN) & treated with 0.1 N HCl. 100 mL of…
Chemistry · JEE Main · NTA Exams — Some Basic Concepts in Chemistry
KOH (V1mL , xN) is mixed with NaOH (V2 mL , yN) & treated with 0.1 N HCl. 100 mL of HCl is required for complete reaction, if V1:V2 = 1:2 & x:y = 2:1. What fraction of HCl is neutralized by NaOH.
- 0.50
- 0.25
- 0.33
- 0.67
Answer
(C) 0.33
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- An oxide of the element contains 20% O 2 by weight. Calculate the equivalent weight of the element?
- An element with atomic mass Z consists of two isotopes of mass number Z - 1 and Z + 2. The percentage…
- How many grams of NaBr could be formed if 14.2 g of NaI are reacted with 40.0 mL of a 0.800 M Br 2 ? 2NaI +…
- NaOH is formed according to the reaction 2 Na + 1 2 O _ 2 Na _ 2 O Na _ 2 O + H _ 2 O 2 NaOH To make 4g of…
- Haemoglobin contains 0.33% of iron by weight. The molecular weight of haemoglobin is approximately 67200 …
- Which of the following have same number of significant figures? A. 0.00253 B. 1.0003 C. 15.0 D. 163 Choose…
- 250 g solution of D-glucose in water contains 10.8% of carbon by weight. The morality (in m) of the solution…
- When 50 mL of 2.00 M HCl, 100 mL of 1.00 M HCl and 100 mL of 0.500 M HCl are mixed together, the resulting…
More Some Basic Concepts in Chemistry questions · Browse all practice questions