A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If…
Physics · JEE Main · NTA Exams — Laws of Motion
A bullet of mass m moving with velocity v strikes a suspended wooden block of mass M. If the block rises to a height h, the initial velocity of the bullet will be :
- \(\sqrt{2 \mathrm{gh}}\)
- \(\frac{M+m}{m} \sqrt{2 g h}\)
- \(\frac{m}{M+m} \sqrt{2 g b}\)
- \(\frac{M-m}{m} \sqrt{2 g h}\)
Answer
(B) M+m m 2 g h
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