The area bounded by the curve y=3+2 x-x^ 2 , y=0 & the ordinate at x=1 x=4 is
Mathematics · JEE Advanced · NTA Exams — Integral Calculus
The area bounded by the curve \(y=3+2 x-x^{2}, y=0\) & the ordinate at \(x=1 \& x=4\) is
- \(25 / 3\)
- \(23 / 3\)
- \(19 / 3\)
- none
Answer
(B) 23 / 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The area of the plane figure bounded in first quadrant by y=x^ 1 / 3 ; y=-x^ 2 +2 x+3 ; y=2 x-1 and the axis…
- If the line x = α divides the area of region R = ( x , y ) ∈ R 2 : x 3 ≤ y ≤ x , 0 ≤ x ≤ 1 into two equal…
- If g(x)= _ 0 ^ x ^ 4 t d t then equals
- Assertion : 1 _ 0 ^ / 2 x x 2 Reason : If is continuous in and m and are greatest and least value of in …
- The value of _ - / 2 ^ / 2 x^ 2 x 1+e^ x d x is equal to
- If is integrable over [1,2] , then _ 1 ^ 2 f(x) d x is equal to
- _ 0 ^ x^ 2 2 x [( / 2) x] 2 x- d x=
- The area of the region ( x, y ) : xy ≤ 8, 1 ≤ y ≤ x 2 is
More Integral Calculus questions · Browse all practice questions