5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its…
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 JK-1 mol-1, calculate ΔU and ΔpV
- ΔU = 14 J; Δ(pV) = 0.8 J
- ΔU = 14 kJ; Δ(pV) = 4 kJ
- ΔU = 14 kJ; Δ(pV) = 18 J
- ΔU = 2.8 kJ; Δ(pV) = 0.8 kJ
Answer
(C) U = 14 kJ; (pV) = 18 J
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