Let S be the set of all solutions of the equation x [- 1 2 , 1 2 ] . Then _ x S 2 ^ -1…
Mathematics · JEE Main · NTA Exams — Trigonometry
Let S be the set of all solutions of the equation
\(x \in\left[-\frac{1}{2}, \frac{1}{2}\right] .\)
Then \(\sum_{x \in S} 2 \sin ^{-1}\left(x^{2}-1\right)\) is equal to
\(x \in\left[-\frac{1}{2}, \frac{1}{2}\right] .\) Then \(\sum_{x \in S} 2 \sin ^{-1}\left(x^{2}-1\right)\) is equal to
- 0
Answer
(A) 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If sin θ and cos θ are the roots of the equation ax 2 – bx + c = 0, then a, b and c satisfy the relation :
- The sum of the radii of inscribed and circumscribed circles for an n sided regular polygon of side a, is
- Given below are two statements. STATEMENT - 1: If cosec - = a ^ 3 and - =b^ 3 then a^ 2 b^ 2 [a^ 2 +b^ 2 ]=1…
- Let ( m , n are co-prime natural numbers) be a solution of the equation (2 ^ -1 x )= 1 9 and let a, b be the…
- The sum of possible value of x for ^ -1 (x+1)+ ^ -1 ( 1 x-1 )
- The solution of ^ -1 x- ^ -1 2 x= 3 is,
- The triangle PQR of which the angles P, Q, R satisfy P = Q 2 R , is
- 8 3 8 5 8 7 8 is equal to