The distance of a point on the ellipse x^ 2 6 + y^ 2 2 =1 from the centre is 2. The…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The distance of a point on the ellipse \(\frac{x^{2}}{6}+\frac{y^{2}}{2}=1\) from the centre is 2. The eccentric angle of the point is
- ± \(\frac{\pi}{2}\)
- ± π
- \(\frac{\pi}{2}, \frac{3 \pi}{4}\)
- ± \(\frac{\pi}{4}\)
Answer
(D) ± 4
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