| a | a |^ 2 - b | ~b |^ 2 |^ 2 =

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. \(|\overrightarrow{\mathrm{a}}|^{2}-|\overrightarrow{\mathrm{b}}|^{2}\)
2. \[\left|\frac{\overrightarrow{\mathrm{a}}-\overrightarrow{\mathrm{b}}}{|\overrightarrow{\mathrm{a}}||\overrightarrow{\mathrm{b}}|}\right|^{2}\]
3. \[\left|\frac{\vec{a}|\vec{a}|-\vec{b}|\vec{b}|}{|\vec{a}||\vec{b}|}\right|^{2}\]
4. none

Answer

(B) | a - b | a || b | |^ 2

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