The possible values of θ ∈ (0, π) such that sin (θ) + sin (4θ) + sin (7θ) = 0 are
Mathematics · JEE Main · NTA Exams — Trigonometry
The possible values of θ ∈ (0, π) such that
sin (θ) + sin (4θ) + sin (7θ) = 0 are
sin (θ) + sin (4θ) + sin (7θ) = 0 are
- \(\frac{2 \pi}{9}, \frac{\pi}{4}, \frac{4 \pi}{9}, \frac{\pi}{2}, \frac{3 \pi}{4}, \frac{8 \pi}{9}\)
- \(\frac{\pi}{4}, \frac{5 \pi}{12}, \frac{\pi}{2}, \frac{2 \pi}{3}, \frac{3 \pi}{4}, \frac{8 \pi}{9}\)
- \(\frac{2 \pi}{9}, \frac{\pi}{4}, \frac{\pi}{2}, \frac{2 \pi}{3}, \frac{3 \pi}{4}, \frac{35 \pi}{36}\)
- \(\frac{2 \pi}{9}, \frac{\pi}{4}, \frac{\pi}{2}, \frac{2 \pi}{3}, \frac{3 \pi}{4}, \frac{8 \pi}{9}\)
Answer
(A) 2 9 , 4 , 4 9 , 2 , 3 4 , 8 9
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