The orbital angular momentum of an electron in 2s orbital is (1992)
Chemistry · JEE Advanced · NTA Exams — Atomic Structure
The orbital angular momentum of an electron in 2s orbital is (1992)
- \(+\frac{1}{2} \cdot \frac{\mathrm{~h}}{2 \pi}\)
- zero
- \(\frac{\mathrm{h}}{2 \pi}\)
- \(\sqrt{2} \cdot \frac{\mathrm{~h}}{2 \pi}\)
Answer
(B) zero
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