A block of mass m is placed on a smooth wedge of inclination . The whole system is…
Physics · JEE Main · NTA Exams — Laws of Motion
A block of mass m is placed on a smooth wedge of inclination \(\theta\). The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be
- \(\frac{m g}{\cos \theta}\)
- \(m g \cos \theta\)
- \(m g \sin \theta\)
Answer
(B) m g
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A shell of mass 20 kg at rest explodes into two fragments whose masses are in the ratio 2 : 3. The smaller…
- A particle of mass 15 kg and initial velocity v _ i = i -2 j m/s. It collides with another body and the…
- In an elevator moving vertically up with an acceleration ‘g’, the force exerted on the floor by a passenger…
- Given below are two statements. STATEMENT - 1: The frictional force always acts in a direction so as to…
- Consider the following two statements : (A) Linear momentum of a system of particles is zero (B) Kinetic…
- A bullet of mass 0.01 kg and travelling at a speed of 500 ~ms ^ -1 strikes a block of 2 kg, which is…
- A 1 kg block and 0.5 kg block move together on a horizontal frictionless surface. Each block exerts a force…
- Given below are two statements. STATEMENT - 1: The coefficient of restitution for a perfectly inelastic…
More Laws of Motion questions · Browse all practice questions