If 2 sin x + 1 ≥ 0 and x ∈ [0, 2π], then the solution set for x is
Mathematics · JEE Advanced · NTA Exams — Trigonometry
If 2 sin x + 1 ≥ 0 and x ∈ [0, 2π], then the solution set for x is
- \(\left[0, \frac{7 \pi}{6}\right]\)
- \(\left[0, \frac{7 \pi}{6}\right] \cup\left[\frac{11 \pi}{6}, 2 \pi\right]\)
- \(\left[\frac{11 \pi}{6}, 2 \pi\right]\)
- None of these
Answer
(B) [0, 7 6 ] [ 11 6 , 2 ]
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