If A= [ array ll 1 & 0 1 & 1 array ] then A –n is equal to -
Mathematics · JEE Main · NTA Exams — Matrices and Determinants
\(\text { If } A=\left[\begin{array}{ll}
1 & 0 \\
1 & 1
\end{array}\right]\) then A–n is equal to -
- \(\left[\begin{array}{ll} 1 & 0 \\ \mathrm{n} & 1 \end{array}\right]\)
- \(\left[\begin{array}{cc} 1 & 0 \\ -\mathrm{n} & -1 \end{array}\right]\)
- \(\left[\begin{array}{cc} 1 & 0 \\ -\mathrm{n} & 1 \end{array}\right]\)
- none of these
Answer
(C) [ array cc 1 & 0 - n & 1 array ]
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