The current in a LR circuit builds up to 3 4 h of its steady state value in 4s. The time…
Physics · JEE Advanced · NTA Exams — Electromagnetic Induction and Alternating Currents
The current in a LR circuit builds up to \(\frac{3}{4} h\) of its steady state value in 4s. The time constant of this circuit is
- \(\frac{1}{\ell \mathrm{n} 2} \mathrm{~s}\)
- \(\frac{2}{\ell \mathrm{n} 2} \mathrm{~s}\)
- \(\frac{3}{\ell \mathrm{n} 2} \mathrm{~s}\)
- \(\frac{4}{\ell \mathrm{n} 2} \mathrm{~s}\)
Answer
(B) 2 n 2 ~s
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