The wave number of the spectral line in the emission spectrum of hydrogen will be equal…
Chemistry · NEET · NTA Exams — Structure of Atom
The wave number of the spectral line in the emission spectrum of hydrogen will be equal to \(\frac{8}{9}\) times the Rydberg constant if the electron jumps from:
- n = 3 to n = 1
- n = 10 to n = 1
- n = 9 to n = 1
- n = 2 to n = 1
Answer
(C) n = 9 to n = 1
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