The number of optical active isomers possible for CH _ 3 CH = C = CHCH _ 3 is
Chemistry · JEE Main · NTA Exams — Some Basic Principles of Organic Chemistry
The number of optical active isomers possible for
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{C}=\mathrm{CHCH}_{3}\) is
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{C}=\mathrm{CHCH}_{3}\) is
- 2
- 3
- 6
- 8
Answer
(A) 2
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