If f(x)=(1+x)^ then the value of f(0)+f^ (0)+ f^ (0) 2! + + f^ (0) n! is
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
If \(f(x)=(1+x)^{\top}\) then the value of \(f(0)+f^{\prime}(0)+\frac{f^{\prime \prime}(0)}{2!}+\ldots \ldots+\frac{f^{\prime \prime}(0)}{n!}\) is
- n
- 2n
- 2n - 1
- None of these
Answer
(D) None of these
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