Two numbers x and y chosen at random (without replacement) from amongst the numbers…
Mathematics · JEE Main · NTA Exams — Statistics and Probability
Two numbers x and y chosen at random (without replacement) from amongst the numbers \(1,2,3, \ldots, 3 n\). Then the probability that \(x^{3}+y^{3}\) is divisible by 3.
- \(\frac{1}{4}\)
- \(\frac{1}{2}\)
- \(\frac{1}{6}\)
- \(\frac{1}{3}\)
Answer
(D) 1 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A random variable X has the probability distribution X 1 2 3 4 5 6 7 8 P(X) 0.15 0.23 0.12 0.10 0.20 0.08…
- If the mean deviation of numbers 1_ 1 1+d_ 1 1+2 d_ 1 .1+100 d from their mean is 255, then d is equal to
- Statement–I: The mean and variance for first n natural numbers are n +1 2 and n ^ 2 +1 12 , respectively…
- There are n-persons sitting in a row. Two of them are selected at random. The probability that two selected…
- If each observation of a raw data whose variance is ^ 2 , is multiplied by , then the variance of the new set…
- Out of 40 consecutive natural numbers, two are chosen at random. Probability that the sum of the numbers is…
- A & B are two independent witnesses (i.e. no collusion between them). The probability that A will speak the…
- Let A and B be two events such that the probability that exactly one of them occurs is 2 5 and the…
More Statistics and Probability questions · Browse all practice questions