The correct order for acid strength of compounds C H C H _ 1 C H _ 3 - C C H and C H _ 2…
Chemistry · NEET · NTA Exams — Some Basic Principles and Techniques
The correct order for acid strength of compounds
\(\mathbf{C H} \equiv \mathbf{C} \mathrm{H}_{1} \mathbf{C} \mathrm{H}_{\mathbf{3}}-\mathbf{C} \equiv \mathbf{C H} \text { and } \mathbf{C H}_{\mathbf{2}}=\mathbf{C H}_{\mathbf{2}}\)
- \(C H_{2}=C H_{2}>C H_{3}-C \equiv C H>H C \equiv C H\)
- \(\mathrm{Hc} \equiv \mathrm{cH}>\mathrm{cH}_{3}-\mathrm{c} \equiv \mathrm{cH}>\mathrm{cH}_{2}=\mathrm{c} \mathrm{H}_{2}\)
- \(\mathrm{cH}_{3}-\mathbf{c} \equiv \mathbf{c H}>\mathrm{cH}_{2}=\mathbf{c} \mathrm{H}_{2}>\mathrm{HC} \equiv \mathbf{c H}\)
- \(C H_{3}-C \equiv C H>C H \equiv C H>C H_{2}=C H_{2}\)
Answer
(B) Hc cH > cH _ 3 - c cH > cH _ 2 = c H _ 2
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