Two springs A and B have force constants k A and k B such that k B = 2k A . The four ends…
Physics · JEE Main · NTA Exams — Work, Energy and Power
Two springs A and B have force constants kA and kB such that kB = 2kA. The four ends of the springs are stretched by the same force. If energy stored in spring A is E, then energy stored in spring B is:
- \(\frac{\mathrm{E}}{2}\)
- 2 E
- E
- 4E
Answer
(A) E 2
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