Two metallic plates of equal lengths and thermal conductivities k 1 and k 2 are put…
Physics · JEE Main · NTA Exams — Thermodynamics
Two metallic plates of equal lengths and thermal conductivities k1 and k2 are put together such that their ends coincide. If their cross-sectional areas are the same, then the equivalent thermal conductivity of the combination will be :
- \(\frac{\mathrm{k}_{1} \mathrm{k}_{2}}{\mathrm{k}_{1}+\mathrm{k}_{2}}\)
- \(\frac{2 \mathrm{k}_{1} \mathrm{k}_{2}}{\mathrm{k}_{1}+\mathrm{k}_{2}}\)
- \(\frac{k_{1}+k_{2}}{2}\)
- \(\sqrt{\mathrm{k}_{1} \mathrm{k}_{2}}\)
Answer
(C) k_ 1 +k_ 2 2
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