The shown P–V diagram represents the thermodynamic cycle of an engine, operating with an…
Physics · JEE Advanced · NTA Exams — Kinetic Theory of Gases
The shown P–V diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is:


- P0V0
- \(\left(\frac{13}{2}\right) P_{0} V_{0}\)
- \(\left(\frac{11}{2}\right) P_{0} V_{0}\)
- 4P0V0
Answer
(B) ( 13 2 ) P_ 0 V_ 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Statement-1: Internal energy change is zero if the temperature is constant, irrespective of the process being…
- Which of the following statement(s) is (are) correct regarding the root mean square speed ( u rms ) and…
- An ideal gas is taken from the state A (pressure P , volume V ) to the state B (pressure P /2, volume 2 V…
- An ideal gas of density ρ = 0.2 kg m –3 enters a chimney of height h at the rate of α = 0.8 kg s –1 from its…
- Statement-1: In an isothermal process whole of the heat energy supplied to the body is converted into…
- When an ideal gas (γ = 5/3) is heated under constant pressure, then what percentage of given heat energy will…
- If the distribution of molecular speeds of a gas is as per the figure shown below, then the ratio of the most…
- At room temperature, the rms speed of the molecules of a certain diatomic gas is found to be 1930 m/s. The…
More Kinetic Theory of Gases questions · Browse all practice questions