Two parallel conductors carrying current of 4.0 A and 10.0 A are placed 2.5 cm apart in…
Physics · Class 12 · CBSE — Moving Charges and Magnetism
Two parallel conductors carrying current of 4.0 A and 10.0 A are placed 2.5 cm apart in vacuum. The force per unit length between them is
- \(6.4 \times 10^{-5} \mathrm{~N} / \mathrm{m}\)
- \(6.4 \times 10^{-2} \mathrm{~N} / \mathrm{m}\)
- \(4.6 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
- \(3.2 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
Answer
(D) 3.2 10^ -4 ~N / m
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