Let ax 7 + bx 6 + cx 5 + dx 4 + ex 3 + fx 2 + gx + h = | array ccc ( x +1) & ( x ^ 2 +2 )…
Mathematics · JEE Advanced · NTA Exams — Matrices and Determinants
Let ax7 + bx6 + cx5 + dx4 + ex3 + fx2 + gx + h
= \[\left|\begin{array}{ccc} (\mathrm{x}+1) & \left(\mathrm{x}^{2}+2\right) & \left(\mathrm{x}^{2}+\mathrm{x}\right) \\ \left(\mathrm{x}^{2}+\mathrm{x}\right) & (\mathrm{x}+1) & \left(\mathrm{x}^{2}+2\right) \\ \left(\mathrm{x}^{2}+2\right) & \left(\mathrm{x}^{2}+\mathrm{x}\right) & \mathrm{x}+1 \end{array}\right|\]. Then
= \[\left|\begin{array}{ccc} (\mathrm{x}+1) & \left(\mathrm{x}^{2}+2\right) & \left(\mathrm{x}^{2}+\mathrm{x}\right) \\ \left(\mathrm{x}^{2}+\mathrm{x}\right) & (\mathrm{x}+1) & \left(\mathrm{x}^{2}+2\right) \\ \left(\mathrm{x}^{2}+2\right) & \left(\mathrm{x}^{2}+\mathrm{x}\right) & \mathrm{x}+1 \end{array}\right|\]. Then
- g = 3 and h = – 5
- g = –3 and h = – 5
- g = – 3 and h = – 9
- None of these
Answer
(D) None of these
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