Find all possible values of x satisfying : [x] [x-2] - [x-2] [x] = 8 x +12 [x-2][x]…

Mathematics · JEE Advanced · NTA ExamsSets, Relations and Functions

Find all possible values of x satisfying :
\(\frac{[x]}{[x-2]}-\frac{[x-2]}{[x]}=\frac{8\{x\}+12}{[x-2][x]}\) 
(where [ ] denotes the greatest function { } is fractional part).
  1. \(\left\{4, \frac{11}{2}\right\}\)
  2. {4, 5}
  3. \(\left\{5, \frac{11}{2}\right\}\)
  4. \(\left\{\frac{11}{2}, \frac{15}{4}\right\}\)

Answer

(A) 4, 11 2

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Sets, Relations and Functions questions · Browse all practice questions