Find all possible values of x satisfying : [x] [x-2] - [x-2] [x] = 8 x +12 [x-2][x]…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
Find all possible values of x satisfying :
\(\frac{[x]}{[x-2]}-\frac{[x-2]}{[x]}=\frac{8\{x\}+12}{[x-2][x]}\)
(where [ ] denotes the greatest function { } is fractional part).
\(\frac{[x]}{[x-2]}-\frac{[x-2]}{[x]}=\frac{8\{x\}+12}{[x-2][x]}\)
(where [ ] denotes the greatest function { } is fractional part).
- \(\left\{4, \frac{11}{2}\right\}\)
- {4, 5}
- \(\left\{5, \frac{11}{2}\right\}\)
- \(\left\{\frac{11}{2}, \frac{15}{4}\right\}\)
Answer
(A) 4, 11 2
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