The magnetic field within a long, straight solenoid with a circular cross section and…

Physics · JEE Advanced · NTA ExamsElectromagnetic Induction and Alternating Currents


The magnetic field within a long, straight solenoid with a circular cross section and radius R is increasing at a rate of dB/dt.
The magnitude of the induced electric field inside the solenoid at a distance r1 from its axis is
  1. \(\frac{r_{1}}{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
  2. \(\mathrm{r}_{1} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
  3. \(\frac{3 \mathrm{r}_{1}}{2} \frac{\mathrm{~dB}}{\mathrm{dt}}\)
  4. \(\frac{\mathrm{r}_{1}}{\sqrt{2}} \frac{\mathrm{~dB}}{\mathrm{dt}}\)

Answer

(A) r_ 1 2 ~dB dt

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