A particle of mass 0.1 kg is executing SHM of amplitude 0.1 m. When the particle passes…
Physics · JEE Main · NTA Exams — Oscillations and Waves
A particle of mass 0.1 kg is executing SHM of amplitude 0.1 m. When the particle passes through the mean position, its K.E. is 8 × 10–3 J. The equation of motion of the particle, when the initial phase of oscillation is 45o, is
- \(y=0.1 \sin \left(3 t+\frac{\pi}{4}\right)\)
- \(y=0.1 \cos \left(3 t+\frac{\pi}{4}\right)\)
- \(y=0.1 \sin \left(4 t+\frac{\pi}{4}\right)\)
- \(y=0.1 \cos \left(4 t+\frac{\pi}{4}\right)\)
Answer
(C) y=0.1 (4 t+ 4 )
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