The EMF of the cell Mg | Mg 2+ (0.01 M)| |Sn 2+ (0.1M)| Sn at 298 K is (Given E ^ _ Mg ^…
Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry
The EMF of the cell
Mg | Mg2+ (0.01 M)| |Sn2+ (0.1M)| Sn at 298 K is (Given \(\mathrm{E}^{\circ}{ }_{\mathrm{Mg}^{2+/} \mathrm{Mg}}=-2.34 \mathrm{~V},\)\(\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{\circ}=-0.14 \mathrm{~V}\))
Mg | Mg2+ (0.01 M)| |Sn2+ (0.1M)| Sn at 298 K is (Given \(\mathrm{E}^{\circ}{ }_{\mathrm{Mg}^{2+/} \mathrm{Mg}}=-2.34 \mathrm{~V},\)\(\mathrm{E}_{\mathrm{Sn}^{2+} / \mathrm{Sn}}^{\circ}=-0.14 \mathrm{~V}\))
- 2.17 V
- 2.23 V
- 2.51 V
- 2.45 V
Answer
(B) 2.23 V
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