An alpha nucleus of energy 1 2 m v^ 2 bombards a heavy nuclear target of charge Ze. Then…
Physics · Class 12 · CBSE — Atoms
An alpha nucleus of energy \(\frac{1}{2} m v^{2}\) bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
- \(\frac{1}{m}\)
- \(\frac{1}{Z e}\)
- v2
- \(\frac{1}{v^{4}}\)
Answer
(A) 1 m
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