The number points (x, y), where curves |y| = l n |x| and (x –1) 2 + y 2 – 4 = 0 cut each…
Mathematics · JEE Advanced · NTA Exams — Sets, Relations and Functions
The number points (x, y), where curves |y| = ln |x| and
(x –1)2 + y2 – 4 = 0 cut each other, is
(x –1)2 + y2 – 4 = 0 cut each other, is
- 2
- 3
- 1
- 6
Answer
(B) 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let f , g and h be real-valued functions defined on the interval [0, 1] by f ( x ) = e x 2 + e – x 2 , g ( x…
- Let E = 1, 2, 3, 4 and F = 1, 2 , then the number of onto functions from E to F is
- f( x )= | x |+ x 3 x is defined for :
- Assertion : ^ -1 x- x^ 2 2 + x^ 3 4 - = d 2 - ^ -1 x^ 2 - x^ 4 2 + x^ 6 4 for 0 Reason : ^ -1 x(x+1) + ^ -1…
- Let f : x, y, z → a, b, c be a one-one function and only one of the conditions (i) f (x) ≠ b, (ii) f (y), = b…
- The domain of the function y = l og 10 l og 10 l og 10 ... l og 10 x is ....... n times .......
- The range of the function f (x) = |x – 1| + |x – 2|, –1 < x < 3, is
- Suppose f ( x ) = ( x + 1) 2 for x ≥ – 1. If g ( x ) is the function whose graph is the reflection of the…
More Sets, Relations and Functions questions · Browse all practice questions