Electrode potential data are given below : array ll Fe _ ( aq ) ^ +3 + e ^ - Fe _ ( aq )…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
Electrode potential data are given below :
\[\begin{array}{ll} \mathrm{Fe}_{(\mathrm{aq})}^{+3}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}_{(\mathrm{aq})}^{+2} ; & \mathrm{E}^{\circ}=+0.77 \mathrm{~V} \\ \mathrm{Al}_{(\mathrm{aq})}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}_{(\mathrm{s})} ; & \mathrm{E}^{\circ}=-1.66 \mathrm{~V} \\ \mathrm{Br}_{2(\mathrm{aq})}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}_{(\mathrm{aq})}^{-} ; & \mathrm{E}^{\circ}=+1.08 \mathrm{~V} \end{array}\]
Based on the data, the reducing power of Fe2+, Al and Br– will increase in the order
\[\begin{array}{ll} \mathrm{Fe}_{(\mathrm{aq})}^{+3}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}_{(\mathrm{aq})}^{+2} ; & \mathrm{E}^{\circ}=+0.77 \mathrm{~V} \\ \mathrm{Al}_{(\mathrm{aq})}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}_{(\mathrm{s})} ; & \mathrm{E}^{\circ}=-1.66 \mathrm{~V} \\ \mathrm{Br}_{2(\mathrm{aq})}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}_{(\mathrm{aq})}^{-} ; & \mathrm{E}^{\circ}=+1.08 \mathrm{~V} \end{array}\]
Based on the data, the reducing power of Fe2+, Al and Br– will increase in the order
- Br– < Fe2+ < Al
- Fe2+ < Al < Br–
- Al < Br– < Fe2+
- Al < Fe2+ < Br–
Answer
(A) Br – 2+ < Al
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