Two identical containers A and B with frictionless pistons contain the same ideal gas at…
Physics · JEE Advanced · NTA Exams — Kinetic Theory of Gases
Two identical containers A and B with frictionless pistons contain the same ideal gas at the same temperature and the same volume V. The mass of the gas in A is mA, and that in B is mB. The gas in each cylinder is now allowed to expand isothermally to the same final volume 2V. The changes in the pressure in A and B are found to be ΔP and 1.5 ΔP respectively. Then
- 4mA = 9mB
- 2mA = 3mB
- 3mA = 2mB
- 9mA = 4mB.
Answer
(A) 4 m A = 9 m B
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