If y = f ( 2 x-1 x^ 2 +1 ) and f ′ (x) = sin x 2 , then dy dx is equal to

Mathematics · JEE Main · NTA ExamsLimit, Continuity and Differentiability

If y = f \(\left(\frac{2 x-1}{x^{2}+1}\right)\) and f ′ (x) = sin x2, then \(\frac{\mathrm{dy}}{\mathrm{dx}}\) is equal to
  1. \[\sin \left(\frac{2 x-1}{x^{2}+1}\right)^{2}\left\{\frac{x^{2}+2 x+2}{\left(x^{2}+1\right)^{2}}\right\}\]
  2. \[\sin \left(\frac{2 x-1}{x^{2}+1}\right)^{2}\left\{\frac{2+2 x-2 x^{2}}{\left(x^{2}+1\right)^{2}}\right\}\]
  3. \[\sin \left(\frac{2 x-1}{x^{2}+1}\right)^{2}\left\{\frac{2+2 x-x^{2}}{\left(x^{2}+1\right)}\right\}\]
  4. None of these

Answer

(B) ( 2 x-1 x^ 2 +1 )^ 2 2+2 x-2 x^ 2 (x^ 2 +1 )^ 2

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