What length of the wire (specific resistance 48 10 -8 m) is needed to make the resistance…
Physics · Class 12 · CBSE — Current Electricity
What length of the wire (specific resistance 48 \(\times\) 10-8 \(\Omega\) m) is needed to make the resistance of 4.2 \(\Omega\) ? (Diameter = 0.4 mm)
- 1.1 m
- 3.1 m
- 2.1 m
- 4.1 m
Answer
(C) 2.1 m
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The specific resistance of a conductor increases with:
- Which pair of readings of ideal voltmeter and ideal ammeter in the given circuit is possible when a suitable…
- A wire of resistance 10 is elongated by 10%. The resistance of the elongated wire is:
- A block of pure silicon at 300 K has a length of 10 cm and an area of 1.0 cm 2 . A battery of emf 2 V is…
- A battery of 16 V and internal resistance 2D is connected to an external resistance R. Find the value of…
- The masses of two cylindrical wires of copper are in the ratio of 1 : 3 and their lengths are in the ratio of…
- Two cells of emf 2 V and 3 V, and internal resistance 1 and 2 , respectively are connected in parallel. The…
- A wire of radius r has resistance R. If it is stretched to the wire of r2 radius, then the resistance becomes:
More Current Electricity questions · Browse all practice questions