When Cu ^ 2+ ion is treated with KI, a white precipitate, X appears in solution. The…

Chemistry · JEE Main · NTA Exams — Redox Reactions and Electrochemistry

1. \(X=\mathrm{Cu}_{2} I_{2}, Y=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{5}\)
2. \(X=C u_{2} I_{2}, Y=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}\)
3. \(X=\mathrm{CuI}_{2}, Y=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{3}\)
4. \(X=\mathrm{CuI}_{2}, Y=\mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}\)

Answer

(B) X=C u_ 2 I_ 2 , Y= Na _ 2 ~S _ 4 O _ 6

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