The half-cell reaction for the corrosion H + + O 2 + 2 e – → H 2 O ; E ° = 1.23 V, Fe 2+…
Chemistry · JEE Advanced · NTA Exams — Electrochemistry
The half-cell reaction for the corrosion
H+ +
O2 + 2e– → H2O ; E° = 1.23 V,
Fe2+ + 2e–→ Fe(s) ; E° = – 0.44 V
find theDG° (in kJ) for the overall reaction.
H+ +
O2 + 2e– Fe2+ + 2e–
find the
- –76
- –322
- –161
- –152
Answer
(B) –322
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