Two positive ions, each carrying a charge q, are separated by a distance d. If F is the…
Physics · JEE Main · NTA Exams — Electrostatics
Two positive ions, each carrying a charge q, are separated by a distance d. If F is the force of repulsion between the ions, the number of electrons missing from each ion will be (e being the charge on an electron)
- \(\frac{4 \pi \epsilon_{a} F d^{2}}{e^{2}}\)
- \(\sqrt{\frac{4 \pi \epsilon_{a} F e^{2}}{d^{2}}}\)
- \(\sqrt{\frac{4 \pi \epsilon_{a} F d^{2}}{e^{2}}}\)
- \(\frac{4 \pi \epsilon_{a} F d^{2}}{q^{2}}\)
Answer
(C) 4 _ a F d^ 2 e^ 2
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