The integral _ 0 ^ 1+4 ^ 2 x 2 -4 x 2 d x equals :
Mathematics · JEE Main · NTA Exams — Integral Calculus
The integral \(\int_{0}^{\pi} \sqrt{1+4 \sin ^{2} \frac{x}{2}-4 \sin \frac{x}{2}} d x\) equals :
- \(4 \sqrt{3}-4-\frac{\pi}{3}\)
- π–4
- \(\frac{2 \pi}{3}-4-4 \sqrt{3}\)
- \(4 \sqrt{3}-4\)
Answer
(A) 4 3 -4- 3
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