For the process : CO 2 (s) → CO 2 (g)

Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics


 For the process : CO2(s) \(\text { → }\) CO2(g)
  1. Both ∆H and ∆S are +ve
  2. ∆H is –ve, ∆S is +ve
  3. ∆H is +ve, ∆S is –ve
  4. Both ∆H and ∆S are –ve.

Answer

(A) Both ∆ H and ∆ S are +ve

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