The length of the common chord of the circles (x – a) 2 + y 2 = c 2 and x 2 + (y – b) 2 =…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
The length of the common chord of the circles (x – a)2 + y2 = c2 and x2 + (y – b)2 = c2 is-
- \(\sqrt{c^{2}+a^{2}+b^{2}}\)
- \(\sqrt{4 c^{2}+a^{2}+b^{2}}\)
- \(\sqrt{4 c^{2}-a^{2}-b^{2}}\)
- \(\sqrt{c^{2}-a^{2}-b^{2}}\)
Answer
(C) 4 c^ 2 -a^ 2 -b^ 2
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